C# and AX Development: Complex Queries in AX

[Blog bot]

Источник: http://olondono.blogspot.com/2008/03/queries-in-ax.html
==============

Overview from Axaptapedia - Expressions in query ranges

For build complex queries, we can use any field, but normally, DataAreaId is used.

query = new Query();
dsInventTable = query.addDataSource(tableNum(InventTable));

// Add our range
queryBuildRange = dsInventTable.addRange(fieldNum(InventTable, DataAreaId));

Query values:

queryBuildRange.value(strFmt('((ItemType == %1) || (ItemId == "%2"))', 
    any2int(ItemType::Service),
    queryValue("B-R14")));

Working with dates:

queryBuildRange.value(strFmt('(ModifiedDate > %1)', Date2StrXpp(01012000)));

Complex queries with relations:

query = new Query();
dsInventTable = query.addDataSource(tableNum(InventTable), tableStr(InventTable));
dsInventItemBarCode = dsInventTable.addDataSource(tableNum(InventItemBarCode), tableStr(InventItemBarCode));
dsInventItemBarCode.relations(true);
dsInventItemBarCode.joinMode(JoinMode::ExistsJoin);
 
// Add our two ranges
queryBuildRange1 = dsInventTable.addRange(fieldNum(InventTable, DataAreaId));
queryBuildRange2 = dsInventItemBarCode.addRange(fieldNum(InventItemBarCode, DataAreaId));

queryBuildRange2.value(strFmt('(ModifiedDate > InventTable.ModifiedDate)'));

Or

queryBuildRange2.value(strFmt('((%1.%2 == %3) || ((%1.%2 == %4) && (%1.%5 == %6)))',
    query.dataSourceTable(tableNum(InventTable)).name(), // InventTable %1
    fieldStr(InventTable, ItemType), // ItemType %2
    any2int(ItemType::Service), // %3
    any2int(ItemType::Item), // %4
    fieldStr(InventTable, ItemId), // ItemId %5
    fieldStr(InventItemBarCode, ItemId))); // %6

Dimensions:


From http://axapta.blogcu.com/387572/

queryBuildRange.value(strFmt('((Dimension == %1) || (Dimension2_ == "%2"))',     "some dim1 value",    "some dim2 value"));

Or

queryBuildRange = dsLedgerTrans.addRange(fieldId2Ext(fieldNum(LedgerTrans, Dimension),1));

Источник: http://olondono.blogspot.com/2008/03/queries-in-ax.html

[kashperuk]

Я правильно понимаю, что приведенный выше код с Dimension2_ работать не будет?

[Alex_KD]

Цитата:

Сообщение от kashperuk

Я правильно понимаю, что приведенный выше код с Dimension2_ работать не будет?

Угу. О чем в первоисточнике написано (в дискусии)